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3 years ago

Que es él valor dé 9 en asistencia

Mathematics

1 answer:

timurjin [86]3 years ago

4 0

No sé lo siento esqje necesito mas puntos lol hahaha

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In a class of 25 students, 18 were math majors, 12 were computer science majors, and 7 were dual majors in math and computer sci

Ber [7]

Answer:

Use n(u) formula of chapter sets

Step-by-step explanation:

Have a good day

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3 years ago

Which point is NOT a solution of the inequality graphed below?

Murljashka [212]

Answer:

Step-by-step explanation:

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3 years ago

3y to the power of 2 +6y+2y

Dafna1 [17]

Answer:

3y2 + 8y

Step-by-step explanation:

3y2 + 6y + 2y

3y2 + 8y

7 0

3 years ago

Determine how long it will take an object to rotate through 6.9 revolutions at an angular velocity of 3.1 radians per second. Us

gregori [183]

Answer: 13 . 99 seconds

Step-by-step explanation:

The formula to find how long it will take an object to rotate through 6.9 revolutions at an angular velocity is given as :

t = 2π x number of revolutions / angular velocity

Therefore :

t = 2π x 6.9 / 3.1

t = 2 x 3.142 x 6.9 / 3.1

t = 43.3596/3.1

t = 13. 98696774194

to the nearest tenth

t = 13. 99s

7 0

3 years ago

supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

4 0

3 years ago