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Explain the difference between properties of equality and properties of inequality when solving equations and inequalities

algol [13]

Answer: An equality is a statement of equal measure. It stands for an absolute statement, without any leeway. That is, there is only a set number of solutions they can take.

Here is an example: x + 17 = 20

In this case, x can only take one solution because it is an absolute statement. Obviously, these can change, but conceptually, they will contain a set of answers a variable can take.

An equality with degree of n will inevitably have n number of answers a variable can take.

However, there are more solutions x can take for an equality. This is because inequality signs are a broader set of equality signs.

Example: x + 17 > 20

In the previous example, there was only one solution that x can take, namely x = 3. However, if we have an inequality, we're merely finding all sets of values x can take that will keep this statement true. In this case, there are an infinite amount of solutions, provided x is greater than 3.

Properties of inequalities vs equalities

This segment is quite tricky to grasp, because we are so used to the equality. The hardest section is to determine when to change the inequality sign. Whenever we multiply or divide by a negative number, we must flip the sign.

8 0

2 years ago

Read 2 more answers

A graph of a line has an x-intercept of 4

Reil [10]

The answer looks like it could be b

8 0

2 years ago

COMPLETE A TABLE OF VALUE FOR EACH EQUATIONS, THEN GRAPH.

gregori [183]

It’s is 1)

A black kid black white white shirt with green green red black

4 0

2 years ago

Solve this system by substitution. y = 6x - 6 y = -4x - 6 *Remember to write your answer as a coordinate point (x, y).

Lisa [10]

Answer: (0, -6)

Explanation:
6x - 6 = -4x - 6
10x = 0
x = 0
y = 6(0) - 6
y = 0 - 6
y = -6

7 0

3 years ago

An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. (a) Use a bin

Advocard [28]

Answer:

a) 0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

b) 0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

Step-by-step explanation:

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

To use the Poisson approximation for the binomial, we have that:

$\mu = np$

1 in every 2500 automobiles produced has a particular manufacturing defect.

This means that $p = \frac{1}{2500} = 0.0004$

a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 7000 cars.

This is $P(X = 4)$ when $n = 7000$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{7000,4}.(0.0004)^{4}.(0.9996)^{6996} = 0.1558$

0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

(b) The Poisson distribution can be used to approximate the binomial distribution for large values of n and small values of p.

Using the approximation:

$\mu = np = 7000*0.0004 = 2.8$ . So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 4) = \frac{e^{-2.8}*(2.8)^{4}}{(4)!} = 0.1557$

0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

6 0

3 years ago