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2 years ago

X+3y=6 graph in linear equation

Mathematics

1 answer:

kotykmax [81]2 years ago

3 0

If you want to put this in slope intercept form, you need to get y alone. To do this, you first need to subtract x from both sides. Then, divide both sides by 3. Your work should look like this:

x + 3y = 6 ( - x both sides)

3y = -x + 6 (Divide both sides by 3)

y = - 1/3 x + 2

***** This is your new equation. This is easier to graph because it gives the slope and the y intercept. *******************************************************

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If you scale a figure by less than or less than 100% does the new copy increase or decrease in size? PLS HURRY IT'S LATE PLS I D

prisoha [69]

Answer:

Less

Step-by-step explanation:

100% is full size

6 0

2 years ago

A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.

Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is $80 $(1.05)^{\textrm t}$ .

Step-by-step explanation:

Given as :

The earning of manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × $(1+ \dfrac{\textrm rate}{100})^{\textrm Time}$

Or, A(t) = $ 80 × $(1+ \dfrac{\textrm 5}{100})^{\textrm t}$

or, A(t) = $ 80 × $(1.05)^{\textrm t}$

Hence The amount that plant earns per man hour after (t) years it open is $80 $(1.05)^{\textrm t}$ . Answer

3 0

3 years ago

Read 2 more answers

Mandy Riddell’s gross weekly pay as a physician’s assistant is $750. Using the tax rates for Social Security of 6.25%, determine

Mashcka [7]

U have to divide the big to the small

6 0

3 years ago

Please help me on this

dlinn [17]

Answer:

-q

Step-by-step explanation:

We know that we are trying to find an expression equivelant to p - q:

p - q can be p - 1q

We can then put parenthesis around -1q:

p + (-1q)

We then can simplify:

p + (-q)

5 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago