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NikAS [45]
3 years ago
10

What is the area of a triangle whose vertices are D(3,3) , E(3,−1) , and F(−2,−5)? ?= Unit ^2

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
5 0
Length of DE = 3-(-1) = 4

SIDE DE is a vertical line 

horizontal distance between E and F is  3 - (-2) = 5

So the area of triangle DEF = 0.5 * 4 * 5 = 10 sq units
rosijanka [135]3 years ago
4 0
Hope this helps you!

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True [87]

Given:

Compound shape

To find:

The area of the compound shape.

Solution:

The compound shape is splitted into two parallelograms.

<u>Bottom parallelogram:</u>

Base = 7.5 cm

Height = 5 cm

Area of the parallelogram = base × height

                                           = 7.5 × 5

                                           = 37.5 cm²

The area of the Bottom parallelogram 37.5 cm².

<u>Top parallelogram:</u>

Base = 7.5 cm

Height = 4.5 cm

Area of the parallelogram = base × height

                                           = 7.5 × 4.5

                                           = 33.75 cm²

The area of the top parallelogram 33.75 cm².

Compound shape = 37.5 + 33.75

                               = 71.25 cm²

The area of the compound shape is 71.25 cm².

7 0
3 years ago
A computer store buys a computer system at a cost of $370.80. Then selling price was first at $618, but then the store advertise
Charra [1.4K]

Answer:

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Step-by-step explanation:

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3 0
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X/7=-6 so solve for x
IgorC [24]

Answer:x-24

Step-by-step explanation:

Solve for xby simplifying both sides of the equation, then isolating the variable.

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1) Moving a figure around a fixed point in the plane is called making a _ _ _
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Answer:

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Step-by-step explanation:

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Anit [1.1K]
34/50= .68 or 68%

hope it helps
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3 years ago
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