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3 years ago

What is the area of a triangle whose vertices are D(3,3) , E(3,−1) , and F(−2,−5)? ?= Unit ^2

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

5 0

Length of DE = 3-(-1) = 4

SIDE DE is a vertical line

horizontal distance between E and F is 3 - (-2) = 5

So the area of triangle DEF = 0.5 * 4 * 5 = 10 sq units

rosijanka [135]3 years ago

4 0

Hope this helps you!

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Answer:

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Step-by-step explanation:

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$R = \sqrt{\frac{A}{\pi } }$

$R = \sqrt{\frac{113}{\pi } }$

$R = \sqrt{36}$

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Use the following diagram and information to answer the question.

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Answer:

b) Julie can use properties of congruent triangles to show that AB≅BC and BC≅CD. Then she can show BC≅AD because opposite sides of a parallelogram are congruent

Step-by-step explanation:

On the assumption that Julie must show all four sides to be congruent, the one remaining step after using the properties of congruent triangles is to show that side AD is congruent to the rest of the sides. Answer choice B describes that.

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47 * 44,580
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2 years ago

A student starts at (0,0) and walks to (12, 0), turns and then walks to (7,12). What is the total distance that this student wal

Harman [31]

Answer:

Step-by-step explanation:

(0,0) to (12,0) => the distance = 12

(12,0) to(7,12) => the distance =

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3 years ago

Write an equation of a line in slope-intercept form that passes through (-3,5) and is parallel to y = -6x +1.

katrin2010 [14]

Answer:

a) The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

b) Slope - intercept form

y = - 6 x - 13

c) The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

Step-by-step explanation:

Step(i):-

Given the equation of the straight line

y = -6x +1

6 x + y - 1 = 0

The equation of the Parallel line to the given straight line is

6x + y + k=0 and it passes through the point (-3, 5 )

⇒ 6 (-3 ) + 5 + k =0

⇒ - 18 + 5 + k=0

⇒ -13 + k = 0

⇒ k = 13

The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

Step(ii):-

Slope - intercept form

y = m x + C

y = - 6 x - 13

Step(iii):-

Intercept - form

6 x + y + 13 =0

6 x + y = - 13

$\frac{6x + y}{-13} = \frac{-13}{-13}$

$\frac{6x}{-13} + \frac{y}{-13} = 1$

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

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2 years ago