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NikAS [45]
3 years ago
10

What is the area of a triangle whose vertices are D(3,3) , E(3,−1) , and F(−2,−5)? ?= Unit ^2

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
5 0
Length of DE = 3-(-1) = 4

SIDE DE is a vertical line 

horizontal distance between E and F is  3 - (-2) = 5

So the area of triangle DEF = 0.5 * 4 * 5 = 10 sq units
rosijanka [135]3 years ago
4 0
Hope this helps you!

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Evaluate the formula V= Bh/3 for B = 15 in.2 and h = 28 in.
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V = Bh/3
V = 15 x 28 / 3 
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V = 140 in^3
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Solve r = 1/2m^2p for p
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3 years ago
Which side lengths cannot form a triangle?
sineoko [7]

Answer:

answer is option A

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3 years ago
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Write the explicit rule,
meriva

Answer:

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Step-by-step explanation:

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d = 52 - 32 = 72 - 52 = 92 - 72 = 20

This indicates the sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

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7 0
2 years ago
The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole
deff fn [24]

Answer:

The length of the flagpole be 41.2 ft .

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Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

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tan \theta = \frac{Perpendicular}{Base}

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2.75 = \frac{AB}{15}

AB = 2.75 × 15

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Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

4 0
3 years ago
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