<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
Answer:
y = 4x - 9
Step-by-step explanation:
Same slope, so they're parallel
F(x) = 30.eˣ
We notice that the graph intercept y-axis at 30
in f(x) = 30.eˣ , for x=0, e⁰ =1 and f(x) = 30
In short it's the only function that has a y-intercept = 30 (answer B)
