Full Question:
The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?
Answer:
the 11 the term is 5120
Step-by-step explanation:
Given
Geometry Progression
4th term = 40
10th term = 2560
Required
11 term.
The nth term of a geometric sequence is calculated as follows
Tₙ = arⁿ⁻¹
For the 4th term, n = 4 and Tₙ = 40
Substitute these in the given formula; this gives
40 = ar⁴⁻¹
40 = ar³. --;; equation 1
For the 10th term, n = 10 and Tₙ = 2560
Substitute these in the given formula; this gives
2560 = ar¹⁰⁻¹
2560 = ar⁹. --;; equation 2
Divide equation 2 by 1. This gives
2560/40 = ar⁹/ar³
64 = r⁹/r³
From laws of indices
64 = r⁹⁻³
64 = r⁶
Find 6th root of both sides
(64)^1/6 = r
r = (2⁶)^1/6
r = 2
Substitute r = 2 in equation 1
40 = ar³. Becomes
40 = a * 2³
40 = a * 8
40 = 8a
Divide both sides by 8
40/8 = 8a/8
5 = a
a = 5.
Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11
So,
Tₙ = arⁿ⁻¹ becomes
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹⁰
Tₙ = 5 * 1024
Tₙ = 5120.
Henxe, the 11 the term is 5120
Answer:
Rs. 451.2
Step-by-step explanation:
It is given that a men's total taxable income is Rs. 14,280.
He is charged by the state tax for 2% on the first Rs. 3000.
i.e. 
= Rs. 60
Then he is asked to pay 3% on the second Rs. 3000
i.e. 
= Rs. 90
Similarly, he pays 3% on the third Rs. 3000
i.e.
= Rs. 90
Lastly, he pays 4% on the remaining amount. i.e 14,280 - (3000+3000+3000) = 14,280 - 9000 = Rs. 5280
∴
= Rs. 211.2
Thus the total amount of the income tax the man has to pay is
= 60+90+90+211.2
= Rs. 451.2
Answer:
$14700
Step-by-step explanation:
$1500=total money paid
1 year has 12 months × 4 years=48 months
48 mths×$275 =$13200
total money paid=
$13200+$1500=
$14700
Answer:
B. x = -6
Step-by-step explanation:
Use a graphing calculator such as desmos and enter each equation, you'll find the only one that falls on (-6, -9) and is perpendicular is B.
30% is equivalent to the fraction 3/10
As 3/10 cannot be simplified anymore, it is your final answer.
