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Inessa05 [86]
3 years ago
9

What Is 9 5/7 - 3 6/7 equals too? ANSWER FAST!!!!!!!

Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Answer:

The answer is 41/7 or 5 6/7

Step-by-step explanation:

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How many pounds of margarine does Joel have if he has eleven<br> quarter-pound sticks?
Anarel [89]

Answer:

2.75

Step-by-step explanation:

1/4 x 11 = 2.75

7 0
3 years ago
Does anyone know how to do this?
marysya [2.9K]

Answer:

Slope intercept form is y = mx + b

m is slope

b is y intercept

y = -4/5x + -9

I only know that first one sry

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given an actual demand of 59, a previous forecast of 64, and an alpha of .3, what would the forecast for the next period be usin
marshall27 [118]

Answer:

62.5

Step-by-step explanation:

Data provided in the question:    

Actual demand = 59  

Previous forecast = 64  

Alpha = 0.3  

Now,    

The  forecast for the next period be using simple exponential smoothing will be given as      

= [ Alpha × Actual demand ] + [ (1 - Alpha) × Previous forecast ]  

= 0.3 × 59 + [ ( 1 - 0.3 ) × 64 ]    

= 17.7 + 44.8      

= 62.5

4 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!
Alex Ar [27]

Start by distributing the exponent to each of the terms in (2u)^{3}.  This will become 2^{3} u^{3}, and 2^{3} =8.  Now, the expression is:

\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }.


We can now simplify the bottom to read: 8u^{5} because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

\frac{2u^{3} v^{2} }{8u^{5} }


The 2/8 simplifies to 1/4:

\frac{u^{3} v^{2} }{4u^{5} }


Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

\frac{v^{2} }{4u^{2} }


Hope this makes sense!!


4 0
4 years ago
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
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