Answer:
The number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his mean (58)
Step-by-step explanation:
A normal random variable with mean Mu = 58 and standard deviation sd = 11 is standardized with the transformation (z-score):
Z = (X - Mu) / sd = (X - 58) / 11
For a value of 74 for X, Z = (74 - 58) / 11 = 1.4545 > 0.
The z-score when X = 74 is 1.4545 > 0
This means that the number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his average (58)
The composition of two translations could describe the taxicab’s final position are (1, -2 + 16) and (1, -2 - 16)
<h3>How to determine the composition of two translations?</h3>
The initial position is given as:
Cab = (1, -2)
Assume the cab travel in one direction, the possible translations are:
(x, y + 16)
(x, y - 16)
(x + 16, y)
(x - 16, y)
Using the first two translations, the final positions are:
(1, -2 + 16) = (1, 14)
(1, -2 - 16) = (1, -18)
Hence, the composition of two translations could describe the taxicab’s final position are (1, -2 + 16) and (1, -2 - 16)
Read more about translations at:
brainly.com/question/8959437
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0.08 is the answer I believe
Answer:
maybe it's 9 not sure though if it's wrong sorry
