How do you determine if the association on a scatter plot is strong or weak

1 answer:

3 0

If the dots on the scatter plot are widely spread out and not in a specific pattern, it is a weak scatter plot. I hope this helped and please mark me brainliest!

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A firm produces 16,200 units at a total cost of $37,585.60. Find the cost per unit to the nearest cent.

Julli [10]

There are a total of 16 200 units with a total costs of 37 585.60 dollars. Now, Given with the choices for the answer, let's find out which one is correct. To be able to get the answer, simply divide the total costs, with the total number of units. => 37 585.60 dollars / 16 200 units => 2.3201 dollars per unit.Next, we need to round this cents to the nearest given options.Since the number next to hundredths is less than 5 , the let's round it to : => 2.32. - this is the correct answer.<span>
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3 0

3 years ago

At camp in Green Bay, Wisconsin, 7/9 of the participants were from Wisconsin. Of that group 3/5 were 12 years old. What fraction

In-s [12.5K]

Since the problem stated that 7/9 of the participants were from Wisconsin, so 2/9 of it were not from Wisconsin. Now out of 7/9 participants, 3/5 of them were 12 years old, so 2/5 of them are not 12 years old. Since we now know the fractions, we'll get the equation 7/9 x 3/5 multiply 7 and 3 then divide it to the product of 9 and 5 to have the answer of 7/15. 7/15 of the participants of the camp in Green Bay is from Wisconsin and are 12 years old.

4 0

3 years ago

Read 2 more answers

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.