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3 years ago

14

Si disponemos de 4 sillas y los simbolizamos por 4s y por otros lados tenemos 2 mesas los simbolizamos por 2m, al reducir los té

rminos semejantes obtendremos lo siguiente.
a) 45
b) 2m
c) 45 - 2m
d) 45 + 2m

2 answers:

Arisa [49]3 years ago

4 0

The answer is I had it before

Alja [10]3 years ago

3 0

It’s should be letter b I hope you have a great day

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The slope of a line perpendicular to the line whose equation is y = 3x - 4 is

trapecia [35]

Answer:

m = -1/3

Step-by-step explanation:

y = 3x-4

This is in slope intercept form

y = mx+b m is the slope and b is the y intercept

The slope is 3 and the y intercept is -4

We want the slope of a line that is perpendicular

Perpendicular lines have slopes that multiply to -1

Let m be the slope of the line that is perpendicular

3 * m = -1

Divide each side by 3

3m/3 = -1/3

m = -1/3

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3 years ago

Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.

natulia [17]

$\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k$

Divergence is easier to compute:

$\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}$

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Curl is a bit more tedious. Denote by $D_t$ the differential operator, namely the derivative with respect to the variable $t$ . Then

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$\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k$

$\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k$

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4 years ago

Find the missing number (1+_ ÷7+4)÷8=4/7

GaryK [48]

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3 years ago

Factor completely 6n^2-18n

lubasha [3.4K]

6n^2-18n

1.find your GCF
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3 years ago

Which of the following functions I which of the following functions are one to one? Select all that apply there are 3 answers

ivann1987 [24]

Answer:

The function $f(x)=\frac{x-1}{3x+3}$ is one-to-one function ⇒ 1st

The function $f(x)=\sqrt{5x+9}$ is one-to-one function ⇒ 2nd

The function $f(x)=\frac{1}{2}x^{3}$ is one-to-one function ⇒ 4th

Step-by-step explanation:

* Lets explain how to solve this problem

- One to one function is the function that has no reputation in the value

of the y-coordinates for every corresponding x-coordinates

- That means when you draw a horizontal line at any value of y, then

the horizontal line intersects the graph of the function at one point

only

- So to solve the problem look to the attached figures

# The red graph of the function $f(x)=\frac{x-1}{3x+3}$ ⇒1st graph

- In this graph if we draw a horizontal line at any value of y it will

intersect the graph at only one point

- Take care there is a horizontal asymptote at y= 1/3, that means

there is no value of x at y = 1/3

∴ The function $f(x)=\frac{x-1}{3x+3}$ is one-to-one function

# The blue graph of the function $f(x)=\sqrt{5x+9}$ ⇒2nd graph

- In this graph if we draw a horizontal line at any value of y it will

intersect the graph at only one point

∴ The function $f(x)=\sqrt{5x+9}$ is one-to-one function

# The green graph of the function $f(x)=\frac{1}{2}x^{3}$ ⇒3rd graph

- In this graph if we draw a horizontal line at any value of y it will

intersect the graph at only one point

∴ The function $f(x)=\frac{1}{2}x^{3}$ is one-to-one function

# The purple graph of the function $f(x)=\frac{7}{4x^{2}}$ ⇒5th graph

- In this graph if we draw a horizontal line at any value of y it will

intersect the graph at more than one point

∴ The function $f(x)=\frac{7}{4x^{2}}$ is not one-to-one function

# The black graph of the function $f(x)=3x^{4}+7x^{3}$ ⇒4th graph

- In this graph if we draw a horizontal line at any value of y it will

intersect the graph at more than one point

∴ The function $f(x)=3x^{4}+7x^{3}$ is not one-to-one function

* The answers are 1st , 2nd and 4th functions

8 0

3 years ago