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Rama09 [41]
3 years ago
8

Plzs help up till 13 please!

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0
15
 1.5
.15
.015
5
.5
1.5
2.5
6.5
1.5
.15
.25
.35
when finding the midpoint its the number equally between the two numbers
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A baseball player reaches first base 20% of the times he is at bat. Out of 70 times at bat, about how many
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Roughly 14 times as 20% of 70 is 14.

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Find the value of x in the picture please
Arada [10]

Answer:

Option D 74°

Step-by-step explanation:

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

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254° and (360-254)=106°

therefore

∠x=(1/2)[254°-106°]

∠x=(1/2)[148°]

∠x=74°

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The number of pages in an Algebra book is 99 less than the number of pages in a geometry book.
san4es73 [151]

Answer: An equation is *629 = n - 99. The geometry book has 728 pages*

Step-by-step explanation: The Algebra book has 99 pages LESS than the geometry book, in other words, the geometry book has 99 pages MORE than the Algebra book. This equation can be used to find the answer. I’m afraid 530 is not the answer.

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4 0
3 years ago
For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.
Sati [7]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.


<span>The sample space S in our problem is as follows: </span>

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

C(12, 2)=\displaystyle{  \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66

So there are in total, 5*66= 330 possible triples.

n(S)=330


The event E "selecting 2 freshmen and 1 junior" can occur in :

C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40 many ways.


so n(E)=40


P(E)=n(E)/n(S)=40/330=0.12



Answer: 0.12


 

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3 years ago
Find polynomial from zeros<br> Zeros 3i,2-i
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