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Mrrafil [7]
3 years ago
11

A certain candle is designed to last nine hours. However, depending on the wind, air bubbles in the wax, the quality of the wax,

and the number of times the candle is re-lit, the actual burning time (in hours) is a uniform random variable with a = 5.5 and b = 9.5.
Suppose one of these candles is randomly selected.
(a) Find the probability that the candle burns at least six hours.
(b) Find the probability that the candle burns at most seven hours.
(c) Find the mean burning time. Find the probability that the burning time of a randomly selected candle will be within one standard deviation of the mean. (Round your answer to four decimal places.)
(d) Find a time t such that 25% of all candles burn longer than t hours.
Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

Step-by-step explanation:

a) P(X > 6) = (9.5-6)/(9.5-5.5) = 3.5/4 = 0.875

b) P(X < 7) = (7-5.5)/(9.5-5.5) = 1.5/4 = 0.375

c) E(X) = (9.5+5.5)/2 = 7.5

Standard deviation = (9.5-5.5)/sqrt(12) =4/3.46 = 1.154

P= 1.156*2/(9.5-5.5) = 2.308/4 = 0.577

d) P(X > t) = 0.25

 (9.5-t) /(9.5-5.5) = 0.3

9.5-t = 1.2

t = 9.5-1.2 = 8.3

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Step-by-step explanation:

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A

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From the graph, we can see that the <em>temperature increased initially</em>, then <em>started to decrease</em>. <u>All of these NOT in a constant rate, though</u>.

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Simplify expression X^2+x-2/x^3-x^2+2x-2
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Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


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Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


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7 0
3 years ago
2y-____=0;y=0 HELPPPPPPP
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Answer:

<em>D.)  0</em>

Step-by-step explanation:

Its not A.  cause 2y−2=0  is y = 1

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It IS D. cause 2y − 0 = 0  is y=0

<em>So you are Correct!!!</em>

<em>hope I helped... <3</em>

<em>Good luck dear :)</em>

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