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vfiekz [6]
2 years ago
7

A twelve cm candle and an 18 cm candle are lit at 6pm. The 12 cm candle burns 0.5cm every hour. The 18cm candle burns 2 cm every

hour. At what time will the two candles be the same height?
Mathematics
1 answer:
Alex73 [517]2 years ago
8 0
The size of the candle 12cm will be reduced as follows:
12-0.5x (x are hours), an the size of the candle 18cm will be reduced as follows: 18-2x, so if you want to find at what time both will be the same height only match the two equations: 12-0.5x=18-2x and solvr for x.
-0.5x+2x=18-12
1.5x=6
x=6/1.5=4 this means 4 hours
If you lit both candles at 6pm then at 10pm they will be the same height
(adittional info: the height will be 10inches) 
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<u>Step-by-step explanation:</u>

Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts   We need to find how many donuts and cream puffs were there . Let's find out:

Let number of donuts and cream puffs are x & y respectively ! So ,

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According to this statement equation is :

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According to this statement equation is :

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Equation (1) & (2) :

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Putting  y=4 in  x=12y-3  :

⇒ x = 12(4)-3

⇒ x = 45

Therefore , donuts and cream puffs were  45 & 4 respectively !

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