The domain is actually the x value of the function, so we need to find the value of x
suppose the width is x, the length is then 3x+5
the area is 50^2 inches, so x(3x+5)=50 => 3x^2+5x-50=0
Factor this quadratic equation: (x-5)(3x+10)=0 =>x=5 or x=-10/3
width can not be negative, so the width is 5
the domain is x=5
y=3 when x=15
this is because we can set up a ratio of when x/15 and set it equal to 6/30 and divide them, solve for x.
Y=-10 and the second one is 13 I think
