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umka2103 [35]
3 years ago
6

28 (A.3A) Determine the slope of the line that

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0
The slope would be -5, I will explain if you would like me to
Dmitry_Shevchenko [17]3 years ago
8 0
The answer is c (-5)
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What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}
Simora [160]

Answer:

domain = ( 3, 11, 121, 34, 23)

range = ( 21, 34, 1, 23)

7 0
3 years ago
The sides of a rectangle are in the ratio 5 : 4. If the perimeter of the rectangle is 360 cm , find its area
djverab [1.8K]

Answer:

Step-by-step explanation:

let, the length is z

thus the ratio will be 5z : 4z

perimeter = 2 (a + b)

360 = 2 ( 5z + 4z )

180 = 9z

z = 20 cm

length = 100 cm and width = 80cm

area = length * width

area = 100*80

area = 8000cm²

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2 years ago
complete the concept map by naming the sampling that you have learned in this module then briefly discuss each
Dmitry [639]

In systematic sampling, individuals are selected at regular intervals from the sampling frame.

<h3>How to explain the sampling?</h3>

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6 0
2 years ago
Callie solved this one-variable equation. When she was done, she tried to verify her answer, but found that it was wrong. Can yo
Molodets [167]

Answer: it is B or number 2

Step-by-step explanation:

I just did it and got it right

5 0
3 years ago
Read 2 more answers
I only need help on the second and third one
Iteru [2.4K]

let's first off notice that, on the 2), the sector is really half of the whole circle, and on 3) the sector is one quarter of the whole circle.

now, on 2) AB is the diameter of 4 units, therefore it has a radius of 2, or half that.

\bf \boxed{2} \\\\\\ \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2 \end{cases}\implies A=\pi 2^2\implies A=4\pi \\\\\\ \stackrel{\textit{half of that}}{A=2\pi}\implies A=\stackrel{\textit{rounded up}}{A=6.3~ft^2} \\\\[-0.35em] ~\dotfill

\bf \boxed{3} \\\\\\ \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=20 \end{cases}\implies A=\pi 20^2\implies A=400\pi \\\\\\ \stackrel{\textit{one quarter of that}}{A=100\pi }\implies \stackrel{\textit{rounded up}}{A=314.2~in^2}

8 0
3 years ago
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