Zeros of this function
- x²-x-6=0
- x²-3x+2x-6=0
- x(x-3)+2(x-3)=0
- (x+2)(x-3)=0
- x={-2,3}
ZEros of reciprocal function
The equation
- x²-(-1/2+1/3)x-(1/2)(1/3)=0
- x²-1/6x-1/6=0
Answer:
2
Step-by-step explanation:
Look at the graph, f(4) is at 3. So what is g(3)? it is 2.
Answer:
Arectangle=27.68cm (approximately)
Step-by-step explanation:
<em>in order to find the area of the rectangle first you need to find the measure of the length and width.</em>
since both of them aren't given ,use trigonometry to find the value of the length and width.
sin30°=opposite/hypotenuse
sin30°=opposite/8cm
opposite=sin30°*8cm. >sin30°=0.5
opposite=4cm
cos30°=adjacent/hypotenuse
cos30°=adjacent/8cm
adjacent=cos30°*8cm. cos30°=0.866
adjacent=6.92cm (approximate value)
Arectangle= bh
Arectangle=4cm*6.92cn
Arectangle=27.68cm
9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
Side length of square (inches): 1 ,2, 4, 7
Perimeter of square (inches). : 4, 8, 16, 28
Step-by-step explanation:
Ratio is 1:4 (S:P).
So:
#:8, #=2. This is because 2/8 and 1/4 both = 0.25.
#:16, #=4. 4/16=0.25
7:#, #=28. 4x7=28, 7/28=0.25
Hope that helps
