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Ahat [919]
3 years ago
10

Write an equation of the line parallel to y=3x+2 that passes through (-1, -2)

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

y=3x+1

Step-by-step explanation:

From the question, we are given;

  • The equation y = 3x + 2
  • A point (-1, -2)

We are required to determine the equation of a line parallel to the given line and passing through the point (-1, -2)

  • We are going to determine the gradient of the line first; when an equation is written in the form of y = mx + c, where m is the gradient.

y = 3x + 2, m₁ = 3

  • But, m₁ = m₂ for parallel lines
  • Therefore, the gradient of the line in question, m₂ is 3
  • With the gradient, m₂=3 , and a point (-1, -2) we can get its equation;

Taking another point (x, y)...

Then;

\frac{y+2}{x+1}=3

y+2=3(x+1)\\y+2=3x+3\\y=3x+1

Therefore; the equation of the line is y=3x+1

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