Answer:
The number of texts she can have is less than 600.
Step-by-step explanation:
Total monthly charge
30 + 0.05 for each text.
So, for x tests, the charge is:
Write an inequality to represent the # of texts she can have?
It has to be under 60, so:
The solution is:
The number of texts she can have is less than 600.
We need the half-life of C-14 which is 5,730 years.
Now, we will need a half-life equation:
elapsed time = half-life * log (bgng amt / ending amt) / log 2
We'll say beginning amount = 100 and ending amount = 41
elapsed time = 5,730 * log (100/41) / log 2
elapsed time = 5,730 * log (
<span>
<span>
<span>
2.4390243902
</span>
</span>
</span>
) / 0.30102999566
elapsed time = 5,730 * 0.38721614327 / 0.30102999566
elapsed time =
<span>
<span>
</span></span><span><span><span>5,730 * 1.2863041851
</span>
</span>
</span>
<span>elapsed time = 7,370.523 years
Source:
http://www.1728.org/halflife.htm </span>
1,5, and 25. 1*25=25 and 5*5=25
Anna has 100 quarters and jazmin has 100 dimes 100 dimes are equal to 10.00 and 100 quarters are equal to 25.00 Anna has more
They will have the same amount of money after 7 weeks.
We first set these equal to each other:
36+4x=x²+15
We want to gather all of the variables on one side. Subtract 4x from both sides:
36+4x-4x=x²+15-4x
36=x²-4x+15
We want the equation to be equal to 0 to solve it, so subtract 36 from both sides:
36-36=x²-4x+15-36
0=x²-4x-21
We can factor this expression. We want factors of -21 that sum to -4; -7(3)=-21 and -7+3=-4:
0=(x-7)(x+3)
Using the zero product property, we know that x-7=0 or x+3=0; this means x=7 or x=-3. Since a negative number of weeks makes no sense, the answer is 7 weeks.
