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3 years ago

Adam is rewriting the expression 8^5/8^2

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

Answer:

8^3

Step-by-step explanation:

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Pls pls help!! ill mark you as brainliest if you get it right!!!

NNADVOKAT [17]

Answer:

the answer is C hope this helps you

8 0

3 years ago

Cross multiply to get answer<br> x + 5/10 = 2x-3/15

Andreyy89

Once cross multiplied you end up with this:

15x+75=20x−30

Next subtract 20x from both sides.

15x+75−20x=20x−30−20x

−5x+75=−30 -----------> Answer

Now subtract 75 from both sides

−5x+75−75=−30−75

−5x=−105

Now divide by -5 on both sides.

-5/-5x = -105/-5

<h3 /><h3>x = 21 --------------> ANSWER</h3>

3 0

3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago

Guys please help as fast as possible.

jolli1 [7]

Answer:theres nothing here to answer

Step-by-step explanation:

4 0

3 years ago

16. Solve for the angle x.<br> cos(¹/2x) = ¹/2

Basile [38]

Answer:

We know that ,

$\rightarrow \tt \cos( \frac{\pi}{3} ) = \frac{1}{2}$

So ,

$\: \rightarrow \tt \cos( \frac{1}{2}x ) = \cos( \frac{\pi}{3} ) \\ \\ \rightarrow \tt \frac{1}{2}.x = \frac{\pi}{3} \\ \\ \rightarrow \tt x = \frac{2\pi}{3}$

we can add 2 pi to it since there will be no change in the value

Also,

$\: \rightarrow \tt \cos( \frac{14\pi}{6} ) = \frac{1}{2} \\ \\ \\ \rightarrow \tt \frac{1}{2} x = \frac{14\pi}{6} \\ \\ \rightarrow \tt x = \frac{7\pi}{3}$

Answer : Option B

6 0

2 years ago