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agasfer [191]
3 years ago
5

Find the balance in the account after the given period. ​$4000 principal earning 4​% compounded​ annually, 5 years

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0
I = P • R • T

= ( 4000 ) ( 0.04 ) ( 5 )

$ 800


NB = I + P

$ 800 + $ 4000
NB = $ 48000
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point Z in nXYZ has coordinates (5,-4). nXYZ was dilated by a scale factor of 0.8 name the coordinates of the image of point V.
cluponka [151]
There is no information given about point V, so any answer will do for the question asked.

If we assume the intent is to ask about the image of point Z, then its coordinates will be 0.8 times those of point Z.
  Z' = 0.8×(5, -4)
  Z' = (0.8×5, 0.8×(-4)) = (4, -3.2)

The appropriate choice seems to be
  C (4, -3.2)
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Let X be a positive continuous random variable with density fXpxq. Let Y " lnpXq. (a) Find the density fY pyq of Y in terms of t
salantis [7]

Answer:

X density = fXpxq and

Y" =InpXq

Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"

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Thus replacing x with y,

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7 0
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Read 2 more answers
Which of the following is the result of the equation below after completing
ICE Princess25 [194]

Answer:

C

Step-by-step explanation:

{x}^{2}  + 5x + 8 = 4 \\  =  >  {x}^{2}  + 2 \times  \frac{5}{2}  \times x +  \frac{25}{4}  +  \frac{7}{4}  = 4 \\  =  >  ({x +  \frac{5}{2} }^{2} ) +  \frac{7}{4}  = 4 \\  =  > ({x +  \frac{5}{2} }^{2} ) =  \frac{9}{4}

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3 years ago
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Evaluate the expression using the values in the left column to complete the table
egoroff_w [7]

Answer/Step-by-step explanation:

A. 4b + 3b

Using b = 2

4(2) + 3(2) = 8 + 6 = 14

Using b = 4

4(4) + 3(4) = 16 + 12 = 28

Using b = 6

4(6) + 3(6) = 24 + 18 = 42

Using b = 8

4(8) + 3(8) = 32 + 24 = 56

Using b = 10

4(10) + 3(10) = 40 + 30 = 70

Using b = 2

4(12) + 3(12) = 48 + 36 = 84

B. 3(x - 2)

Using x = 3

3(3 - 2) = 3(1) = 3

Using x = 5

3(5 - 2) = 3(3) = 9

Using x = 7

3(7 - 2) = 3(5) = 15

Using x = 9

3(9 - 2) = 3(7) = 21

Using x = 11

3(11 - 2) = 3(9) = 27

Using x = 13

3(13 - 2) = 3(11) = 33

C. 5(4a - 1)

Using a = 2

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Using a = 3

5(4(3) - 1) = 5(12 - 1) = 5(11) = 55

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5(4(4) - 1) = 5(16 - 1) = 5(15) = 75

Using a = 5

5(4(5) - 1) = 5(20 - 1) = 5(19) = 95

Using a = 6

5(4(6) - 1) = 5(24 - 1) = 5(23) = 115

Using a = 7

5(4(7) - 1) = 5(28 - 1) = 5(27) = 135

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Using y = 2

6(2) - 2(2) + 4 = 12 - 4 + 4 = 12

Using y = 3

6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16

Using y = 5

6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24

Using y = 10

6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44

Using y = 8

6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36

Using y = 6

6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28

7 0
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