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3 years ago

Find the balance in the account after the given period. $4000 principal earning 4% compounded annually, 5 years

Mathematics

1 answer:

AnnZ [28]3 years ago

8 0

I = P • R • T

= ( 4000 ) ( 0.04 ) ( 5 )

$ 800

NB = I + P

$ 800 + $ 4000
NB = $ 48000

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Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

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A "For every half an hour there is 1/5 of the bucket is filled" Hope I helped
B: Not sure not very good at equations :(
C: Well there is Half an hour so if you multiply that by 5 then its. 2 1/2 hours :)
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Find the balance in the account after the given period. ​$4000 principal earning 4​% compounded​ annually, 5 years

Find the balance in the account after the given period. $4000 principal earning 4% compounded annually, 5 years