All categories

2 years ago

Which term gives the horizontal length of one cycle of a periodic function?

Mathematics

2 answers:

GuDViN [60]2 years ago

8 0

Answer:

frequency

Step-by-step explanation:

Wish that helped!

jeka57 [31]2 years ago

7 0

The period of a function is the horizontal length of one complete cycle. The period may also be described as the distance from one "peak" (max) to the next "peak" (max). This sine curve, y = sin x, has a period of 2π, the horizontal length of one complete cycle.

You might be interested in

the length of a rectangular parking lot at the airport is 2/3 is mile.if the area is 1/2 square mile,what is the width of the pa

ch4aika [34]

Answer:

3/4

Step-by-step explanation:

3/4*2/3+1/2

8 0

2 years ago

HELP PLEASE!! <3 A rectangle has vertices (w,v), (w,z), and (z,z). Find the fourth vertex.

Vaselesa [24]

Answer:

Hey, Try practiceing on your own

Step-by-step explanation:

8 0

2 years ago

At the car show Inez saw a truck wheel shaped like a circle with a radius of 3 ft. She wants to know the area of the truck wheel

Nadusha1986 [10]

Answer:

$28.27ft^2$

Step-by-step explanation:

To solve this problem, we can use the area of a circle formula:

$A=\pi r^2$

A = area

r = radius

Lets plug the values into the equation:

$A=\pi (3^2)$ Calculate $3^2$

$A=\pi (9)$ Multiply $\pi$ and 9 together

$A=28.27$

The area of the truck wheel is $28.27ft^2$

3 0

2 years ago

2x+y=7 for y neeedd help

masya89 [10]

Answer:

y = -2x + 7

Step-by-step explanation:

Solve for y:

2x + y = 7

Add - 2x to both sides

2x + y - 2x = 7 - 2x
y = 7 - 2x

y = -2x + 7

8 0

2 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

2 years ago