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3 years ago

One card is randomly selected from a deck of cards. Find the odds: in favor of getting a spade.

Mathematics

2 answers:

n200080 [17]3 years ago

6 0

Answer:

1/4

Step-by-step explanation:

In a deck of cards, there are 52 cards (not including jokers)

and there are 13 cards that are spades, so it's simply just 13/52 which simplifies to 1/4

Monica [59]3 years ago

3 0

Answer:

1/4 chance or 0.25 or 25%

Step-by-step explanation:

One forth of cards in a deck are spades

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Step-by-step explanation please<br> (Worth 3 marks)

atroni [7]

Answer:

62°

Step-by-step explanation:

180-118=62

62+62=124

180-124=56

118-56=62

5 0

3 years ago

Read 2 more answers

Justo ayer fue el cumpleaños de Mauricio. Si a la edad e Mauricio, le sumo 13, al resultado le resto 10, luego al nuevo resultad

bezimeni [28]

Answer:

Mauricio nació en el año 2000.

Step-by-step explanation:

Supóngase que el cumpleaños se celebra en el año 2020, si $x$ es la edad actual de Mauricio, entonces la expresión matemática que traduce el enunciado del problema es:

$\frac{(x+13)-10}{23} +20 = 21$

Ahora, se desarrolla y se simplifica la ecuación:

$\frac{x+3}{23}+20 = 21$

$\frac{x+3}{23} = 1$

Se despeja $x$ :

$x +3 = 23$

$x = 20$

Mauricio tiene 20 años.

Ahora, el año de nacimiento de Mauricio es la sustracción de la edad de Mauricio del año actual:

$y = 2020-20$

$y = 2000$

Mauricio nació en el año 2000.

3 0

3 years ago

{{{{{PLEASE HELP ASAP}}}}

4vir4ik [10]

Answer:

126

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

2 years ago

What's the slope formula?

ZanzabumX [31]

(y2-y1)/(x2-x1) if you have 2 points
And rise/run on graph

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3 years ago