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Reptile [31]
2 years ago
12

Help me please I need this done quick

Mathematics
1 answer:
Anna11 [10]2 years ago
7 0
Answer:
1058.4 in^2

Step-by-step explanation:
Find the surface areas of the rectangular prism and the triangular prisms separately.
Triangular: S = (1/2)lP+B, where l is slant height, P perimeter, and B base area.
14(4)= 56 perimeter of base
13 slant height
B = 14x14 = 196
put together:
S = (1/2)(13 x 56) + 196
S = 560 in^2

Now the rectangular prism
S = 2lw + 2lh + 2wh, where l is length, h height, w width. (delete the first 2lw since they share one side/they're combined shapes.
S = 2(14x8.9) + 2(14x8.9)
S = 498.4 in^2

Add them together: 498.4 + 560 = 1058.4 in^2
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Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

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