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Reptile [31]
2 years ago
12

Help me please I need this done quick

Mathematics
1 answer:
Anna11 [10]2 years ago
7 0
Answer:
1058.4 in^2

Step-by-step explanation:
Find the surface areas of the rectangular prism and the triangular prisms separately.
Triangular: S = (1/2)lP+B, where l is slant height, P perimeter, and B base area.
14(4)= 56 perimeter of base
13 slant height
B = 14x14 = 196
put together:
S = (1/2)(13 x 56) + 196
S = 560 in^2

Now the rectangular prism
S = 2lw + 2lh + 2wh, where l is length, h height, w width. (delete the first 2lw since they share one side/they're combined shapes.
S = 2(14x8.9) + 2(14x8.9)
S = 498.4 in^2

Add them together: 498.4 + 560 = 1058.4 in^2
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Which of the following is true about a parallelogram?
andriy [413]
The diagonals bisect each other
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A _[blank 1]_ is a number whose only factors are 1 and itself. If a number has other factors besides 1 and itself, it is called
kykrilka [37]

Numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Given a paragraph in which there are blanks:

A _____ is a number whose only factors are 1 and itself. If a number has  factors besides 1 and itself, it is called a _____. You can use divisibility rules or _______ to help you determine whether a number is prime or composite.

We are required to fill the blank with appropriate options.

We have to fill "prime numbers" in the first blank.

We have to fill "composite numbers" in the second blank.

We have to fill "the sieve of Eratosthenes" in the third blank.

Hence numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Learn more about prime numbers at brainly.com/question/145452

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3 0
1 year ago
Ok really need hellp hear
Nuetrik [128]

Answer:

2/3 is the answer..

Step-by-step explanation:

becaue 2 holes then 2/3s is not filled trust me!!! plz give brainliest and a thanks!!!!

6 0
3 years ago
Yi Min is a pitcher on her softball team. This season,
almond37 [142]

Answer:

48

Step-by-step explanation:

0.8 times 60= 48

4 0
3 years ago
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548  approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: 26\times 26\times 26 \times 10 \times 10 \times10

26^3\times 10^3=17576000

The numbers of ways in which two letters followed by four digits can be chosen is: 26\times 26\times 10 \times 10 \times 10 \times10

26^2\times 10^4=6760000

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: 26^2=676

The probability that a randomly chosen plate contains the number 2222 is:

\frac{676}{24336000} \approx 0.000028

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

26\times 1\times10^3+1\times 26\times10^3

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

1\times 10^4

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

1\times 10^4+26\times 1\times10^3+1\times 26\times10^3

62000

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

\frac{62000}{24336000} \approx 0.002548

7 0
3 years ago
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