Answer:
(B)1005 feet
Step-by-step explanation:
In the attached diagram

|AG|=1400 feet
Distance from point C to point G=|CG|
Using Trigonometry in Triangle ACG

Using Trigonometry in Triangle BCG'

Therefore, the distance from balloon B from balloon A
=CG+CG'
=808+197
=1005 feet
The answer is
5mn(KUASA DUA) -6gh(KUASA DUA) +2
Answer:
2
Step-by-step explanation:
"Rise over run"
- It goes up 2
- Over 1
-
simpifies to 2
It moves the graph 5 steps downwards on the y axis.