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4 years ago

Round to the nearest cent $73,028.85316

Mathematics

1 answer:

polet [3.4K]4 years ago

3 0

Answer:

73,028.8520

pretty sure that’s what you’re asking?

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Solve the right triangle below. Round sides to the nearest thousandth and angles to the nearest degree.

aalyn [17]

Answer:

Option 4, BC = 12.689, m∠A = 58°, and m∠C = 32°

Hope this helps!

4 0

3 years ago

What fraction of students prefer Mt Rushmore over Grand Canyon ? Write in simplest form ?

Flura [38]

For 14/28 is simplest form would be 1/2 and 8/28 in simplest form would be 2/7. I hope this helps. ^^

4 0

3 years ago

Read 2 more answers

Polly buys 14 cupcakes for a party. The bakery puts them into boxes that hold 4 cupcakes each.

Temka [501]

Answer:

Part a) The number of boxes needed will be 4

part b) The fraction of the box that is empty is $\frac{1}{2}$

Part c) Are needed 2 cupcakes to fill the last box

Step-by-step explanation:

Part a) How many boxes will be needed for Polly to bring all the cupcakes to the party?

To find out the number of boxes needed, divide the total number of cupcakes by 4 (maximum number of cupcakes that fit in each box).

$\frac{14}{4}=3.5\ box$

Round up

The number of boxes needed will be 4

Part b) If the bakery completely fills as many boxes as possible, what fraction of the last box is empty?

we know that

The maximum number of cupcakes per box is 4

The first three boxes have 4 cupcakes

The last box has

$14-3(4)=2\ cupcakes$

The fraction of the box that is empty is equal to the number of cupcakes missing to fill the box divided by the cupcake capacity of the box

$\frac{2}{4}=\frac{1}{2}$

Part c) How many more cupcakes are needed to fill this box

Subtract the number of cupcakes in the box from the cupcake capacity of the box

The last box has 2 cupcakes

The cupcake capacity of the box is 4

$4-2=2\ cupcakes$

therefore

Are needed 2 cupcakes to fill the last box

8 0

3 years ago

Please help me ive got a limited amount of time

Afina-wow [57]

Answer:

The answer is -3

Step-by-step explanation:

find y-intercept

set x = 0

y = 4(0)-3

y = -3

4 0

3 years ago

When finding out if 2 triangles are congruent, is it possible to only use a side and angle if those are the only 2 provided? Hel

PIT_PIT [208]

Short answer: No and yes.
Yes First.
If the lower right point (looks like an C perhaps or an F) and the middle point and the upper left point lie on the same line and if D the middle point and the upper right point lie n the the same line, then yes. You have angle side angle. The lower right angle is given as equal to the upper left angle. The angles at C are vertically opposite angles and they are equal and you have been given 2 enclosed sides that are equal.

No
If the points I've described are not on the same line, then the triangles are not congruent. If I can, I'll edit this a second time.

Please Note:
You have done something that looks a bit illegal to me. I wouldn't just trade pictures. It only costs you another 5 points to issue another question. I do think, however, that it is very clever. In answering about 1700 questions, I've never seen this done. That's commendable.

8 0

3 years ago

Round to the nearest cent ​$73,028.85316

Round to the nearest cent $73,028.85316