For the first expression
15 + 2d
A possible word problem would be this:
A person saves $2 per day of money. Before he started saving, he had $15 dollars set aside. Look for the expression that expresses the total amount of money saved in terms of the number of days passed
The second expression is
200 - 2m
A possible word problem would be this:
The distance from school to the park is 200m. A kid riding a bike is traveling at a speed of 2m/s from the school to the park. Write an expression for the distance remaining between the park and the kid.<span />
Answer:
Step-by-step explanation:
A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.
A model shows a total of c cups divided into 10 sections, each labeled 2 and 1 fourth.
Part A
Which equation models the total number of cups of flour, c, Henry needs?
c+214=10
214×c=10
10+c=214
214×10=c
Part B
How many cups of flour does Henry need?
2014cups
2212cups
2434cups
2512cups
Part C
Estimate how much flour Henry would need to make 15 batches of cookies. Explain.
I would round 214 to 2, so Henry would need about 30 cups of flour.
I would round 214 to 3, so Henry would need about 45 cups of flour.
I would round 214 to 1, so Henry would need about 15 cups of flour.
I would round 214 to 234, so Henry would need about 30 cups of flour.
Answer: -144.1226
Step-by-step explanation:
Answer:
-30
Step-by-step explanation:
10 x 3 = 30
10 x -3= -30
please mark me brainliest
two negatives makes a positive
two positives markets a negative
and
a positive and a negative makes a negative
Answer:
NUMBER 1.)
Step 1
Subtract 3y3y from both sides.
5x=10-3y5x=10−3y
Step 2
Divide both sides by 55.
\frac{5x}{5}=\frac{10-3y}{5}
5
5x
=
5
10−3y
Hint
Undo multiplication by dividing both sides by one factor.
Step 3
Dividing by 55 undoes the multiplication by 55.
x=\frac{10-3y}{5}x=
5
10−3y
Hint
Undo multiplication.
Step 4
Divide 10-3y10−3y by 55.
x=-\frac{3y}{5}+2x=−
5
3y
+2
Hint
Divide.
Solution
x=-\frac{3y}{5}+2x=−5
3y+2
Step-by-step explanation:
NUMBER 2.)
Step 1
Add 4y4y to both sides.
3x=6+4y3x=6+4y
Step 2
The equation is in standard form.
3x=4y+63x=4y+6
Step 3
Divide both sides by 33.
\frac{3x}{3}=\frac{4y+6}{3}
3
3x
=
3
4y+6
Hint
Undo multiplication by dividing both sides by one factor.
Step 4
Dividing by 33 undoes the multiplication by 33.
x=\frac{4y+6}{3}x=
3
4y+6
Hint
Undo multiplication.
Step 5
Divide 6+4y6+4y by 33.
x=\frac{4y}{3}+2x=
3
4y
+2
Hint
Divide.
Solution
x=\frac{4y}{3}+2x= 3
4y+2