(1) C and (2) D
(1)
distribute the left side of the equation
2h - 16 - h = h - 16 ( simplify left side )
h - 16 = h - 16
Since both sides are equal, any value of h will make the equation true.
Hence there are infinitely many solutions to the equation → C
(2)
3 + 6z = 13 + 6z ( subtract 6z from both sides )
3 = 13 ← not possible
Hence there are no solutions to the equation → D
Here, formula: 5h²
Coefficient = 5
Hope this helps!
Answer:
The question is not so clear and complete
Step-by-step explanation:
But for questions like this, since the equation has been given, what is expected is for us to make comparison, compare the RHS with the LHS or by method of comparing coefficients.
We follow the stated conditions since we are told that b and c are both integers which are greater than 1 and b is less than the product of cb. from these conditions, we can compare and get the values of b , c and d.
Another approach is to assume values, make assumptions with the stated conditions, however, our assumptions must be valid and correct if we substitute the assumed values of b, c and d in the equation, it must arrive at the same answer for the RHS. i.e LHS = RHS
5 units. The only variable changing is x so it's just 5 units up from the second coordinate
Answer:

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...