Given the matrix equation<br><br><br> AX + B = C

What type of correlation/association exists?

LuckyWell [14K]

Answer:

Negative Correlation

Step-by-step explanation:

there is a negative correlation between the number of hours you sleep in and the number of hours you are awake during the day as the longer you are either awake or asleep the less time you will be doing the other thing

Here is a graph I made that will hopefully help you understand.

Even if I switched around the label for the x or y-axis, the correlation would still remain the same because the more you stay asleep, the less you will be awake and vice versa.

3 0

3 years ago

Solve the following equation and check.

madreJ [45]

The solution is x=42

4 0

2 years ago

Read 2 more answers

Please help me ASAP<br> Please help

m_a_m_a [10]

Answer:

5 X 4

Step-by-step explanation:

If you plot the dots, youll obviously see a rectangle. The height of the rect. is 4, while the length is 5, so the measurements would be <em>5 x 4.</em>

<em />

<em>Hope this helped!!</em>

6 0

3 years ago

Find the third order maclaurin polynomial. Use it to estimate the value of sqrt1.3

vodka [1.7K]

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

<h3>Find the third order maclaurin polynomial:</h3>

Given the polynomial,

$f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }$

The formula to find the maclaurin polynomial,

$f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

Next we have to find f'(x), f''(x) and f'''(x),

$f'(x) = \frac{3}{2}(1+3x)^{-\frac{1}{2} }$

$f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }$

$f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }$

By putting x = 0 , we get,

$f(0)=(1+3(0))^{\frac{1}{2} }=1$

$f'(0) = \frac{3}{2}(1+3(0))^{-\frac{1}{2} }=\frac{3}{2}$

$f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}$

$f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}$

Therefore the maclaurin polynomial by using the formula will be,

$\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$

To find the value of $\sqrt{1.3}$ we can use the maclaurin polynomial,

$\sqrt{1.3}$ is $\sqrt{1+3x}$ with x = 1/10,

$\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}$

$\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14$

Hence $\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14.

Learn more about maclaurin polynomial here:

brainly.com/question/24188694

#SPJ1

6 0

1 year ago

Read 2 more answers

Question 3 options: lily is building a picture frame. the larger rectangle represents the frame. the smaller rectangle represent

Finger [1]

The area of the shaded region of this figure which can be calculated by the difference of the larger region from the smaller region would be 104 in.²

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

Area of a larger rectangle

= Length × Width

= 18 × 12

= 216 in.²

Area of the smaller rectangle

Length = 12 - 2 - 2 = 8 in.

Width = 18 - 2 - 2 = 14 in.

= Length × Width

= 8 × 14

= 112 in.²

Area of the shaded region = Area of a larger rectangle - Area of the smaller rectangle

= 216 - 112

= 104 in.²

Hence, the area of the shaded region of this figure is 104 in.²

Learn more about the area;

brainly.com/question/2289492

5 0

2 years ago

Given the matrix equation AX + B = C