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3 years ago

The perimeter of a rectangular garden is 38 m and its area is 60 sq.m. What are the dimensions of the garden?

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Answer:

15m by 4m

Step-by-step explanation:

x + y + x + y = 38

x * y = 60

Substitute

x = 60/y

60/y + y + 60/y + y = 38

y = 15 or 4

x = 15 or 4

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D. Customer who buy at least 25 tickets will pay $1.50 each

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2 years ago

Please OMG I DONT UNDERSTAND

elena-14-01-66 [18.8K]

Answer:

ANSWER

Step-by-step explanation:

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3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

3 years ago

You are working in a small, student-run company that sends out merchandise with university branding to alumni around the world.

topjm [15]

Answer:

The answer is "0.142466".

Step-by-step explanation:

Using the p formula for the proportion of nonconforming units through the subgrouping which can vary in sizes:

$p =\frac{np}{n}\\\\$

$\bar{p}=\frac{\Sigma np}{\Sigma n}\\\\$

Defects $= \frac{5}{100} \times 50 \\\\$

$p = \frac{5}{100} \times \frac{50}{50}=0.05\\\\$

It calculates the controls limits through the p-chart that is:

$UCL_{p},LCL_{p}=\bar{p} \pm \sqrt{\frac{\bar{p}(1-\bar{p})}{\bar{n}}}\\\\$

So, the upper control limits:

$= 0.05 + 3 \times \sqrt{(\frac{0.05\times(1-0.05)}{50})} \\\\= 0.142466$

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2 years ago

40 is 60% of what number?

11111nata11111 [884]

40(60/100) 4(6/10) =24/10 = 2.4

4 0

2 years ago

Read 2 more answers