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natulia [17]
2 years ago
13

What is the solution for a2 -b2

Mathematics
2 answers:
taurus [48]2 years ago
5 0

Answer:

do you mean 2a-2b, cause i don't understand and it remains the same is it is because we don't know what a is and what b is so it stays the same

Step-by-step explanation:

Sphinxa [80]2 years ago
4 0
2(a-b)

this is the answers
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Read 2 more answers
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
3 years ago
What is the solution to the equation below? Round your answer to two decimal places. 4•e^x=17
bixtya [17]

Answer:

\large\boxed{x\approx1.45}

Step-by-step explanation:

4e^x=17\qquad\text{divide both sides by 4}\\\\e^x=\dfrac{17}{4}\qquad \ln\ \text{of both sides}\\\\\ln e^x=\ln\dfrac{17}{4}\qquad\text{use}\ \log_aa^n=n\\\\x=\ln\dfrac{17}{4}\\\\x\approx1.45

7 0
2 years ago
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