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4 years ago

Hellllllllllllppppppppp

Mathematics

1 answer:

const2013 [10]4 years ago

5 0

I can help you. What is your question? Can you tell me?

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Which ordered pairs are solutions to the inequality 2x+y>−4?

alexgriva [62]

Answer:

The ordered pairs are (5,-12), (-1,-1).

Step-by-step explanation:

Given : Inequality $2x+y>-4$

To find : Which ordered pairs are solutions to the inequality ?

Solution :

We put the given options the point which satisfied the equation is the solution.

Inequality $2x+y>-4$

1) (5,-12)

$2(5)+(-12)>-4$

$10-12>-4$

$-2>-4$

It is true.

2) (-1,-1)

$2(-1)+(-1)>-4$

$-2-1>-4$

$-3>-4$

It is true.

3) (-3,0)

$2(-3)+(0)>-4$

$-6+0>-4$

$-6>-4$

It is false.

4) (4,-12)

$2(4)+(-12)>-4$

$8-12>-4$

$-4>-4$

It is false.

Therefore, The ordered pairs are (5,-12), (-1,-1).

4 0

4 years ago

Y=6 X=2 XY+7-Y=??????????????????????

Vlad1618 [11]

If i did my math right it would be 13.

8 0

3 years ago

2/x-5=4x What is the value of x

kati45 [8]

Answer:

$\large\boxed{x=\dfrac{5\pm3\sqrt3}{2}}$

Step-by-step explanation:

$Domain:\ x-5\neq0\to x\neq5\\\\\dfrac{2}{x-5}=4x\\\\\dfrac{2}{x-5}=\dfrac{4x}{1}\qquad\text{cross multiply}\\\\(4x)(x-5)=(2)(1)\qquad\text{use the distributive property}\\\\(4x)(x)+(4x)(-5)=2\\\\4x^2-20x=2\\\\2^2x^2-20x=2\\\\(2x)^2-2(2x)(5)=2\qquad\text{add}\ 5^2\ \text{to both sides}\\\\(2x)^2-2(2x)(5)+5^2=2+5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(2x-5)^2=2+25\\\\(2x-5)^2=27\to2x-5=\pm\sqrt{27}\qquad\text{add 5 to both sides}$

$2x=5\pm\sqrt{9\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\2x=5\pm\sqrt9\cdot\sqrt3\\\\2x=5\pm3\sqrt3\qquad\text{divide both sides by 2}\\\\x=\dfrac{5\pm3\sqrt3}{2}$

3 0

3 years ago

Can somebody please help me out please my grads are bad

Vika [28.1K]

Answer:

a) 10 inches

b) 48 feet

Step-by-step explanation:

10 inches, 60/6 = 10

48 feet, 8*6 = 48

7 0

3 years ago

A snail travels at a rate of 2.36 feet per minute. write a rule to describe the function hoy far Will the snail travel in 6 minu

valentinak56 [21]

distance traveled = (2.36 ft/min)(6 min) = 14.16 ft

5 0

3 years ago