Answer: see below
Step-by-step explanation
Let 2 + a = 11 x
Let 35 - b = 11 y
Where x and y are any unknown integer
subtract the two equations
- 33 + a + b = 11 (x+y)
a+ b = 11 (x+ y) +33
a+ b = 11 (x+y) + 3 (11)
a+ b = 11(x+ y+3)
Which proves that a+b is a factor of 11
Answer:
(x,y)→(y,-x)
Step-by-step explanation:
Parallelogram ABCD:
A(2,5)
B(5,4)
C(5,2)
D(2,3)
Parallelogram A'B'C'D':
A'(5,-4)
B'(4,-5)
C'(2,-5)
D'(3,-2)
Rule:
A(2,5)→A'(5,-2)
B(5,4)→B'(4,-5)
C(5,2)→C'(2,-5)
D(2,3)→D'(3,-2)
so the rule is
(x,y)→(y,-x)
7x+8(x+1/4) = 3(6x-9)-8
7x+8x+2 = 18x - 27 -24
15x + 2 = 18x - 51
+51 + 51
15x + 53 = 18x
-15x = -15x
53 = 3x
17.66 = x
Answer: 37
Step-by-step explanation:
Split the second term in 3a^2 - 8a + 4 into two terms
3a^2 - 2a - 6a + 4 = 0
Factor out common terms in the first two terms, then in the last two terms.
a(3a - 2) -2(3a - 2) = 0
Factor out the common term 3a - 2
(3a - 2)(a - 2) = 0
Solve for a;
a = 2/3,2
<u>Answer : B. (2/3,2)</u>
