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ale4655 [162]
3 years ago
14

What is the length of the diagonal of the square shown below?

Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

7\sqrt{2}

Step-by-step explanation:

Given is a picture of a square with each side = 7 units

Since a square is right angled we have the diagonal bisecting the square into two isosceles right triangles.

Use Pythagorean theorem to get the diagonal length.

Hence diagonal =\sqrt{7^2+7^2} =7\sqrt{2}

Alternate method:

Find the length of the diagonal of a square, multiply the length of one side by the square root of 2: If the length of one side is x, then diagonal will have length as

x\sqrt{2}

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The odds of flipping a fair coin either heads or tails is 50%. The odds of rolling a six on a fair six sided die is 16.6% or 1 i
creativ13 [48]

Answer:

P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.

The final probability will be sum of the above given probabilities.

Hence P( sum is prime )= 73/216

8 0
3 years ago
Please show work i rlly need this :)
makvit [3.9K]

Answer:

10/16 (written as a fraction)

Step-by-step explanation:

Starting point

-(-2x+1)=9-14x

Solve the minus sign

2x-1=9-14x

Swap the Xs and the numbers, changing sign

2x+14x=9+1

Do calculations

16x=10

Result

x=10/16

4 0
3 years ago
Read 2 more answers
Which is the simplified expression for questions 1 2 3 4? (Look at photo)
Anit [1.1K]
1. 9.5x + 1.5
2. 9x + 36
3. 4.8x + 2
4. 22x + 2
6 0
2 years ago
How many zeros in the standard form of 10/3
Slav-nsk [51]

If you meant, "how many zeros are there in the standard form of 'ten divided by 3,' the answer would be, "none."


10/3 = 3.3333333333333.... This is a repeating decimal.


7 0
3 years ago
Betty invests $45,000 into a cd which has an interest rate of 6.3% that compounds monthly for a total of 5 years. how much will
Lelechka [254]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$45000\\ r=rate\to 6.3\%\to \frac{6.3}{100}\dotfill &0.063\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &5 \end{cases} \\\\\\ A=45000\left(1+\frac{0.063}{12}\right)^{12\cdot 5}\implies A=45000(1.00525)^{60}\implies A\approx 61611

5 0
1 year ago
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