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3 years ago

What is the 7th term of the sequence 3,12,48,192

1 answer:

8 0

If you look at this sequence, every term of this sequence is being multiplied by 4.

3 x 4 = 12
12 x 4 = 48
48 x 4 = 192
192 x 4= 768
768 x 4 = 3072
3072 x 4 = 12288

So the 7th term of this sequence is 12288.

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3 years ago

7m+n over q= 2m. How do I solve for q

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3 years ago

Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side. The area of the smalle

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3 years ago

Read 2 more answers

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4 years ago

Find the amount in the bank after 7 years if interest is compounded quarterly?

qwelly [4]

Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

Step-by-step explanation:

We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

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3 years ago