Question

Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms into another atom (polonium-210 in this case) each day. If you begin with 233 mg of Bismuth-210, how much remains after 8 days?

Answer 1

Answer:

Approximately 76.5 mg.

Step-by-step explanation:

Given,

The initial quantity of the Bismuth-210, P = 233 mg,

Also, the rate of decay per day, r = 13 %

Thus, the quantity of the Bismuth-210 after 8 days would be,

$A=P(1-\frac{r}{100})^8$

$=233(1-\frac{13}{100})^8$

$=233(1-0.13)^8$

$=233(0.87)^8$

$=76.4733194697$

$\approx 76.5\text{ mg}$