3 years ago

Can anyone please help me figure this out

Mathematics

1 answer:

Fed [463]3 years ago

5 0

Answer:

x=27

Step-by-step explanation:

please give brainly

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What are the vertex, axis of symmetry, domain and range of the function:

DiKsa [7]

Y=(-x*x)-4x+3
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Answers:
Vertex: (2,-1)
AOS:x = 2
Domain: All Real Numbers
Range:[-1,Infinity)

3 0

3 years ago

ordered pairs in which of these formats do not have to represent a function? (Length of side of a square,perimeter of square)

Daniel [21]

Answer:

perimeter of square

Step-by-step explanation:

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3 years ago

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If A=(9,18) and B=(1,12), what is the length of AB?

Fynjy0 [20]

Use the distance formula?

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3 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

Write the equation: If 6 is subtracted from the product of 3 and a number, the result is 8 more than the number.

Bogdan [553]

<span>Write the equation
</span>
3n - 6 = n + 8

hope it helps

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3 years ago

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Can anyone please help me figure this out ​

Can anyone please help me figure this out