Hope this helps
You have to rearrange the formula
Answer:
x = 4 for Lines U and V to be parallel
<u>Skills needed: HS Geo, Angle Theorems, Equations</u>
Step-by-step explanation:
1) We see that there are two angle measures given to us. There is an angle marked with the measure of 
°, and the other is marked with (
)°.
- First of all, these two angles are categorized alternate interior angles. They are on alternate sides of the transversal, and are within the two lines (not on the outer side of the lines). I will add an image for reference regarding this idea.
- If 2 lines are parallel, alternate interior angles are congruent. This means that:
2) Solving this equation is fairly straightforward.
(add 2 to both sides in order to get the 
by itself. 
(to get 
by itself)- 132 divided by 33 is 4, and 33x divided by 33 is x, so
--------------------------------------------------------------------------------------------------------------Hope you understood, have a great day.
<span> When area is equal 1120. We can write an equation
(x+4)(-x+64)=1120
-x²-4x+64x+256=1120
-x²+60x+256-1120=0
-x²+60x-864=0
D=b² - 4ac= 3600-4*864=144, √D=12
x= (-b+/-√D)/2a
x=(-60+/-12)/(-2)
x=24, x=36
For x=24
(x+4)=24+4=28
(-x+64)=(-24+64)=40
For x=36
(x+4)=36+4=40
(x-64) =(-36+64)=28
So sides should be 28 and 40 in.
We did not get any extraneous solutions. They could be if we get negative length side, for example. They can come because a quadratic equation can
give positive and negative numbers because a^2 and (-a)^2 give the same positive number.
We chose to solve this equation using formula for quadratic equations, because this equation has too big numbers to solve it using other methods.
</span>
3.5 divided by 4.
Each sister will receive 0.875 feet of ribbon.
9514 1404 393
Answer:
a) 10(3x+2) ≤ 140; x ≤ 4
b) no
Step-by-step explanation:
a) The area is the product of length and width. We want that product to be no greater than 140:
10(3x +2) ≤ 140 . . . . your inequality
We can solve this by dividing by 10 first.
3x +2 ≤ 14
3x ≤ 12 . . . . . . subtract 2
x ≤ 4 . . . . . . . . divide by 3; the solution to the inequality
__
b) If the length were 15, the area would be 10×15 = 150, which is greater than 140. The length cannot be 15 if the area is at most 140.
