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Alex
3 years ago
14

Use the picture to answer the question. Angle ABC is rotated 50° around point D . What is the measure of angle A'B'C' ?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
5 0

Answer: A. 90°

Step-by-step explanation:

From the given picture, we can see that the measure of ∠ABC=90°.

Given that Angle ABC is rotated 50° around point D .

We know that a rotation is a rigid transformation that produces an image of a geometric figure with same shape and size by rotating about the the center of rotation.

It preserves the shape and angle inside the figure.

Therefore, ∠A'B'C'=∠ABC=90°.

MissTica3 years ago
4 0

Answer:

A. 90

Step-by-step explanation:

Rotating an angle does not change its measure. ABC is 90 degrees as marked by the corner symbol. After rotating, the angle stays 90 degrees.

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Can i please have some help??
Sliva [168]

Answer:

No solution

Step-by-step explanation:

When lines are parallel, they do not intersect and they do not have a solution.

Thank You

Hope it helps u

3 0
3 years ago
What is the lcd of 11/10 and 1/6
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7 0
3 years ago
Given the parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π. convert to a rectangular equation and sketch the curve
Temka [501]

The rectangular equation for given parametric equations x = 2sin(t) and   y = -3cos(t) on 0 ≤ t ≤ π is  \frac{x^{2} }{4} +\frac{y^2}{9} =1 which is an ellipse.

For given question,

We have been given a pair of parametric equations x = 2sin(t) and           y = -3cos(t) on 0 ≤ t ≤ π.

We need to convert given parametric equations to a rectangular equation and sketch the curve.

Given parametric equations can be written as,

x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.

We know that the trigonometric identity,

sin²t + cos²t = 1

⇒ (x/2)² + (- y/3)² = 1

⇒ \frac{x^{2} }{4} +\frac{y^2}{9} =1

This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.

The rectangular equation is  \frac{x^{2} }{4} +\frac{y^2}{9} =1

The graph of the rectangular equation \frac{x^{2} }{4} +\frac{y^2}{9} =1 is as shown below.

Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is  \frac{x^{2} }{4} +\frac{y^2}{9} =1 which is an ellipse.

Learn more about the parametric equations here:

brainly.com/question/14289251

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7 0
2 years ago
1/2 (4x -2) - 2/3 (6x + 9) ≤ 4
KatRina [158]
Answer: x ≤ -5.5

reason:

first, multiply 4x and -2 by 1/2 and 6x and 9 by -2/3.
this makes the equation 2x-1-4x-6 ≤ 4
combine like terms to make it -2x-7 ≤ 4
add 7 to both sides to get -2x ≤ 11
divide both sides by -2 and get x ≤ -5.5
3 0
4 years ago
Set up your calculator to show the following
Aleksandr [31]

Answer:

the correct answer is h.

Step-by-step explanation:

5 0
3 years ago
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