Here is your answer:
6.78 rounded to the nearest tenth = 7.00 because the 7 in 6.78 is greater then five.
8.21 rounded to the nearest tenth= 8.00 because the 2 in 8.21 is NOT greater than five.
the
complete question in the attached figure
part A
the x intercept 0 is the point where the ball was hit, the x intercept 20 is the point where the ball fell back to the ground, 20 feet away from the kicker.
<span>the function is increasing in the interval x∈(0, 10) and decreasing in x∈(10, 20) </span>
this means that the height is increasing in the interval (0, 10) and decreasing as x goes through the interval (10,20)
the distance from the kicker is increasing during the whole interval (0, 20)
part B
the rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases or increases in the interval
x =[A, B]
from x = 22 to x = 26-------------- > the function does not exist
Just divide 7 by 6 to convert the fraction to decimal form and then compare the two
Let x = the amount of time that the third person needs to work on the job to add up to one
1 = 1/2 + 1/3 + x
1 - 1/2 - 1/3 = x
To subtract the fractions we need to put them all over a common denominator. Let's use 3*2 = 6 as the denominator; so 1 = 6/6, 1/2 = 3/6, 1/3 = 2/6:
6/6 - 3/6 - 2/6 = x
1/6 = x
The third person must work 1/6 time on the project.
Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
81% of students own a wireless device.
This means that 
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So


34.87% probability that all 5 have a wireless device