You start by changing both the a common denominator, this case it would be 100 so it’s 2/100 and 5/100, since 1/50 and 2/100 is the same, each 1/100 is equal to “6” and you have 5/100, which is EQUAL TO 30
If he runs 6.5 metres per second, then you multiply 6.5 by 4 to get 26m
(3640 - 3250) / 3250 = 390 / 3250 = 39 / 325 = 3 / 25 = 12%
(4100 - 3640) / 3640 = 460 / 3640 = 46 / 364 = 23 / 182 = 12.637...%
I think it’s 16
Radius of circle = 32
Diagonal of circle = 64 cm
So 64 divided by 8 = 16
Mark me as brainliest
<h3>
Answer: 127</h3>
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Explanation:
The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.
The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.
Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.
So we have these scores
- first exam = 70
- second exam = 80
- third exam = 43
- fourth exam = x+5
Adding up these scores and dividing by 4 will get us the average
(sum of scores)/(number of scores) = average
(70+80+43+x+5)/4 = 80
(x+198)/4 = 80
x+198 = 4*80
x+198 = 320
x = 320 - 198
x = 122
So the student got a score of x+5 = 122+5 = 127 on the fourth exam.
