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Katyanochek1 [597]
3 years ago
8

If 1⁄50 of an amount is 12, what is 1⁄20?

Mathematics
1 answer:
Alika [10]3 years ago
4 0
You start by changing both the a common denominator, this case it would be 100 so it’s 2/100 and 5/100, since 1/50 and 2/100 is the same, each 1/100 is equal to “6” and you have 5/100, which is EQUAL TO 30
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Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4
ad-work [718]

Answer:

f''(x)=36x^2+4

Step-by-step explanation:

Let's start by finding the first derivative of f(x)= 3x^4+2x^2-8x+4. We can do so by using the power rule for derivatives.

The power rule states that:

  • \frac{d}{dx} (x^n) = n \times x^n^-^1

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

  • \frac{d}{dx} (3x^4+2x^2-8x+4)

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)

Simplify the equation.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)
  • f'(x)=12x^3+4x-8

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

  • \frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)
  • \frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)

Simplify the equation.

  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )

Therefore, this is the 2nd derivative of the function f(x).

We can say that: f''(x)=36x^2+4

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