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3 years ago

9

It takes Amir 4 seconds to run from his front door to the mailbox. If he can run at a top speed of 6.5 m/s, how far is it from h

is front door to the mailbox?

1 answer:

dlinn [17]3 years ago

6 0

If he runs 6.5 metres per second, then you multiply 6.5 by 4 to get 26m

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If a truck averages 12 miles to the gallon, how many pounds of carbon dioxide are emitted into the atmosphere when the truck tra

77julia77 [94]

Answer: 278.30 pounds (if the gasoline does not contain ethanol)

317.12 pounds (if the gasoline does contain ethanol)

Step-by-step explanation:

If the truck averages 12 miles per gallon, then in 170 miles it consumes:

170mi/12mi = 14.17 gallons.

We know that for one gallon consumed, the carbon dioxide emitted into the atmosphere is 19.64 pounds. (assuming it does not contain ethanol)

Then for 14.17 gallons consumed, we have a emission of:

14.17*19.64 pounds = 278.30 pounds

I the gasoline contains ethanlol, for a gallon the emiision is around 22.38 pounds.

In this case the total emission is:

14.17*22.38 pounds = 317.12 pounds

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4 years ago

Help....!! I need to solve this simultaneous equation y=x-2 and y=3x+5 With working out if possible please....

Blababa [14]

Step-by-step explanation:

Y= x - 2. Y = 3x + 5

Putting value of y

x - 2 = 3x + 5

-2 - 5 = 3x - x

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Putting value of x

Y = 3(-7/2) + 5

Y = - 10.5 + 5

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3 years ago

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet

Natali5045456 [20]

Complete Question

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet from the ground and he catches it when it is four feet from the ground,How long is the ball in the air?

Answer:

$t\approx 0.1s$

Step-by-step explanation:

From the question we are told that

Initial velocity $V_0= 18 ft/s$

Initial Height $h_1=5feet$

Final Height $h_2=4feet$

Generally the Newtons equation for motion is mathematically given by

$V^2 = U^2 + 2as$

Where

$s=h_2-h_1\\s=4-5\\s=-1ft$

And

$a=g=>9.81\\a=32.2ft/s^2$

Therefore

$V^2 = (18)^2 + 2(-32.2)(-1)$

$V^2 = 388.4$

$V =19.70786645\\V=19.71ft/s$

Generally the equation for Time is mathematically Given as

$t=\frac{V-U}{a}$

$t=\frac{19.71-18}{32.2}$

$t=0.05310559006$

$t\approx 0.1s$

Therefore the time spent on air by the ball is

$t=0.05310559006s$

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3 years ago

Hurry please I’m running out of time! Show work

agasfer [191]

Answer:125

Step-by-step explanation:

x*25=125 x=125

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castortr0y [4]

Looking at the problem I think the answers are C, D, AND E

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3 years ago