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maria [59]
2 years ago
5

HI I need help please Its in the pictures

Mathematics
1 answer:
Brut [27]2 years ago
8 0
1.

r=32\,\text{units}\\\\
A=\pi\cdot r^2=\pi\cdot32^2=1024\pi\,\,\text{units}^2

Answer D.

2.
From secant theorem, we know, that:

|AE|\cdot|BE|=|DE|\cdot|CE|

and from picture:

|BE|=x+1\\\\|CE|=x+4\\\\|AE|=11+x+1=x+12\\\\|DE|=1+x+4=x+5

So we can calculate:

|AE|\cdot|BE|=|DE|\cdot|CE|\\\\(x+12)\cdot(x+1)=(x+5)\cdot(x+4)\\\\
x^2+12x+x+12=x^2+5x+4x+20\\\\
x^2+13x+12=x^2+9x+20\quad|-x^2\\\\13x+12=9x+20\quad|-9x\\\\4x+12=20\quad|-12\\\\4x=8\quad|:4\\\\\boxed{x=2}
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If 0° ≤ θ ≤ 90° and cosθ = 11/15 , what is the value of sin (90° - θ)?
igor_vitrenko [27]
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first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!

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7 0
3 years ago
Read 2 more answers
Giving brainliest to the answer who gives step by step examples clearly!
Anarel [89]

<em>Hi there!</em>

<em>This should be easy,lol!</em>

<em>Answer:</em>

<em />\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }<em> (Decimal: -221.702503)</em>

<em />\sqrt[3]{162} = \boxed{162 \sqrt{3} }<em> (Decimal: 280.592231)</em>

<em />\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}<em />

<em>Sorry bout the explanation thingy. Their really long -.-!</em>

<em>But the last one is short so i'll put it for you!</em>

<em>Step-by-step explanation:</em>

<em>∴!For the last one!∴</em>

<em />\sqrt[3]{-1000x^4}<em />

<em>Simplifies to:</em>

<em />= - 1732.050808 * x^4<em />

<em />= - 1732.050808 * ( x * x * x * x)<em> </em>

<em />= - 1732.050808x^4<em />

<em>Have a great day/night!</em>

7 0
3 years ago
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number 1:

x>\frac{-7}{2}

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x>-1

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3 years ago
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