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NemiM [27]
2 years ago
11

John runs a computer software store. Yesterday he counted 140 people who walked by the store, 63 of whom came into the store. Of

the 63, only 25 bought something in the store.
(a) Estimate the probability that a person who walks by the store will enter the store. (Round your answer to two decimal places.)
(b) Estimate the probability that a person who walks into the store will buy something. (Round your answer to two decimal places.)
(c) Estimate the probability that a person who walks by the store will come in and buy something. (Round your answer to two decimal places.)
(d) Estimate the probability that a person who comes into the store will buy nothing. (Round your answer to two decimal places.)
Mathematics
2 answers:
Grace [21]2 years ago
8 0

Answer:

.................

Step-by-step explanation:

............

Alik [6]2 years ago
6 0
A. 45%
b. 39.68%
c. 17.86%
d. 60.32%

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6 0
2 years ago
Please help if u see this
jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0
2 years ago
You have 9 1/2 on a poster for a row of photos. Each photo is 2 3/4 inches wide. How many photos can you fit?
Sever21 [200]

Answer:

i wanna say 3

Step-by-step explanation:

i believe its 3 because if you add that 1/2 to the 3/4 you could have a 3 and 3 divided by 9 is 3 (forgive me if incorrect)

4 0
3 years ago
Simplify (-3c^-3w^5)^3<br> A -9w^8<br> B. -27cw^8<br> C. w^15/27c^9<br> D.-27w^15/c^9
kenny6666 [7]

Answer:

\large\boxed{D.\ \dfrac{-27w^{15}}{c^9}}

Step-by-step explanation:

(-3c^{-3}w^5)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\=(-3)^3(c^{-3})^3(w^5)^3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-27c^{-3\cdot3}w^{5\cdot3}=-27c^{-9}w^{15}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-27\left(\dfrac{1}{c^9}\right)w^{15}=\dfrac{-27w^{15}}{c^9}

4 0
3 years ago
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