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3 years ago

A triangle has a base of 10 inches and a height of 4.5 inches. What is the area of the triangle in square inches?

Mathematics

2 answers:

Sergio039 [100]3 years ago

4 0

Answer:

22.5inch²

Step-by-step explanation:

area of a triangle = 1/2 base × height

base = 10 inches, height = 4.5inches

area = 1/2× 10 × 4.5

area = 5×4.5

area = 22.5inch²

STatiana [176]3 years ago

3 0

Answer:

22.5

Step-by-step explanation:

10 x 4.5 = 45 divided by 2 is 22.5

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Answer:

106.25

Step-by-step explanation:

y = 85(1.25) = 106.25

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2 years ago

Use the Pythagorean Theorem to find the length of the leg in the triangle shown below. The figure shows a right triangle with on

Natali5045456 [20]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

I don’t know how to do this

stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as $x$ approaches the edges. For example,

$g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}$

has two pieces, $2x+5$ and $x^2-10$ , both of which are continuous by themselves on the provided intervals. In order for $g$ to be continuous everywhere, we need to have

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)$

By definition of $g$ , we have $g(-3)=2(-3)+5=-1$ , and the limits are

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1$

$\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1$

The limits match, so $g$ is continuous.

For the others: Each of the individual pieces of $f,h$ are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.