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3 years ago

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a polynomial function has a zero at -1,2, and 7( all multiplicity 1) write a function in standard form that could represent this

function

1 answer:

s2008m [1.1K]3 years ago

4 0

Answer:

$x^3-8x^2+5x+14$

Step-by-step explanation:

We have been given the zeroes of polynomial which are -1,2,7

That means the factors are (x+1) (x-2) (x-7)

When we want to a polynomial from zeroes we multiply the factors

$(x+1)(x-2)(x-7)$

$(x+1)(x^2-7x-2x+14)$

$(x+1)(x^2-9x+14)$

$(x^3-9x^2+14x+x^2-9x+14$

$x^3-8x^2+5x+14$

Hence, the required polynomial is:

$x^3-8x^2+5x+14$

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