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Nuetrik [128]
3 years ago
11

a polynomial function has a zero at -1,2, and 7( all multiplicity 1) write a function in standard form that could represent this

function
Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

x^3-8x^2+5x+14

Step-by-step explanation:

We have been given the zeroes of polynomial which are -1,2,7

That means the factors are (x+1) (x-2) (x-7)

When we want to a polynomial from zeroes we multiply the factors

(x+1)(x-2)(x-7)

(x+1)(x^2-7x-2x+14)

(x+1)(x^2-9x+14)

(x^3-9x^2+14x+x^2-9x+14

x^3-8x^2+5x+14

Hence, the required polynomial is:

x^3-8x^2+5x+14

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Answer:8 cup servings. 1/4×8=8/4

Step-by-step explanation:

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3 years ago
Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls
murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222

Hence,

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684

Part b

P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}

Hence,

P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}

4 0
3 years ago
Help needed ASAP it’s geometry
ivanzaharov [21]

Answer:

<h2>           32</h2>

Step-by-step explanation:

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Step-by-step explanation:

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Option A: 6.23 x 1012

Step-by-step explanation:

Please check provided image.

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