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Naddika [18.5K]
3 years ago
8

Ms. Sheppard cuts 1/2 of a piece of construction paper. She uses 1/6 of the piece to make a flower. What fraction of the sheet o

f paper does she used to make flower?
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

1/12

Step-by-step explanation:

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EMERGENCY PLEASE HELP! Which set of ordered pairs does not represent a function?
lilavasa [31]

Answer:

c.

Step-by-step explanation:

The X value 1 is repeated

7 0
3 years ago
WILL MARK THE BRAINLIEST
Elis [28]

Answer:

Option D, 16/21

Step-by-step explanation:

<u>Step 1:  Add all of them together</u>

5 + 7 + 9

21

<u>Step 2:  Figure out how much of the plants are medicinal</u>

7 + 9

16

<u>Step 3:  Figure out the probability </u>

16/21

Answer:  Option D, 16/21

7 0
3 years ago
19/24 as a decimal rounded to the nearest hundreths
Evgen [1.6K]

Answer:

0.79

Step-by-step explanation:

19 / 24 is 0.79166667

So it's 0.79

8 0
3 years ago
Consider a melody to be 7 notes from a single piano octave, where 2 of the notes are white key notes and 5 are black key notes.
igor_vitrenko [27]

Answer:

35,829,630 melodies

Step-by-step explanation:

There are 12 half-steps in an octave and therefore 12^7 arrangements of 7 notes if there were no stipulations.

Using complimentary counting, subtract the inadmissible arrangements from 12^7 to get the number of admissible arrangements.

\displaystyle \_\_ \:B_1\_\_ \:B_2\_\_ \:B_3\_\_ \:B_4\_\_ \:B_5\_\_

B_1 can be any note, giving us 12 options. Whatever note we choose, B_2, B_{...} must match it, yielding 12\cdot 1\cdot 1\cdot 1\cdot 1=12. For the remaining two white key notes, W_1 and W_2, we have 11 options for each (they can be anything but the note we chose for the black keys).

There are three possible arrangements of white key groups and black key groups that are inadmissible:

WWBBBBB\\WBBBBBW\\BBBBBWW

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is \displaystyle\frac{11\cdot 11}{2!}.

Therefore, the number of admissible arrangements is:

\displaystyle 12^7-3\left(\frac{12\cdot 11\cdot 11}{2!}\right)=\boxed{35,829,630}

6 0
2 years ago
Taylor bought 200 shares of stock for $18.12 per share last year. He paid his broker a flat fee of $30. He sold te stock this mo
rusak2 [61]
The answer is $3990 heres why

First you need to find out what is the total you paied for the shares
$18.12x200= $3624

Then you need to add the flat fee to the spending chost
$3624+$30= $3654 

Now you re-mulitply the chost per stock to the tootle #'s of stock you sold
$21x200= $4200

Then you need to find out what how much you need to pay the stock broker
$4200x.05= $210
 
Then once you find out how much you need to pay him subtract that amount to the total money earned from selling your stocks
$4200-$210= $3990 

Then if you want to also find out your profit just subtract the total amount you payed for the stock and subtract it from the total amount you gained from the stock. 
$3990- $3654= $336 Profit 

6 0
3 years ago
Read 2 more answers
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