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photoshop1234 [79]
3 years ago
14

Taylor bought 200 shares of stock for $18.12 per share last year. He paid his broker a flat fee of $30. He sold te stock this mo

rning for $21 per share, and paid his broker 0.5% commission.
What were Taylor's net proceeds?
Mathematics
2 answers:
rusak2 [61]3 years ago
6 0
The answer is $3990 heres why

First you need to find out what is the total you paied for the shares
$18.12x200= $3624

Then you need to add the flat fee to the spending chost
$3624+$30= $3654 

Now you re-mulitply the chost per stock to the tootle #'s of stock you sold
$21x200= $4200

Then you need to find out what how much you need to pay the stock broker
$4200x.05= $210
 
Then once you find out how much you need to pay him subtract that amount to the total money earned from selling your stocks
$4200-$210= $3990 

Then if you want to also find out your profit just subtract the total amount you payed for the stock and subtract it from the total amount you gained from the stock. 
$3990- $3654= $336 Profit 

My name is Ann [436]3 years ago
5 0

Answer:

$555

Step-by-step explanation:

His net proceed is the difference between his net revenue and total cost considering how much was paid to the broker during purchase and sale.

Total cost at purchase = 200 * $18.12 + $30

= 3624 + 30

= $3654

Net revenue = 200 * $21 - 0.5% ( 200 * $21)

= $4179

Net proceeds = $4179 - $3654

= $555

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Use the Chain Rule (Calculus 2)
atroni [7]

1. By the chain rule,

\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}

I'm going to switch up the notation to save space, so for example, z_x is shorthand for \frac{\partial z}{\partial x}.

z_t=z_xx_t+z_yy_t

We have

x=e^{-t}\implies x_t=-e^{-t}

y=e^t\implies y_t=e^t

z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}

\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0

Similarly,

w_t=w_xx_t+w_yy_t+w_zz_t

where

x=\cosh^2t\implies x_t=2\cosh t\sinh t

y=\sinh^2t\implies y_t=2\cosh t\sinh t

z=t\implies z_t=1

To capture all the partial derivatives of w, compute its gradient:

\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}

\implies w_t=\dfrac1{\sqrt{-2t-t^2}}

2. The problem is asking for \frac{\partial z}{\partial x} and \frac{\partial z}{\partial y}. But z is already a function of x,y, so the chain rule isn't needed here. I suspect it's supposed to say "find \frac{\partial z}{\partial s} and \frac{\partial z}{\partial t}" instead.

If that's the case, then

z_s=z_xx_s+z_yy_s

z_t=z_xx_t+z_yy_t

as the hint suggests. We have

z=\sin x\cos y\implies\begin{cases}z_x=\cos x\cos y=\cos(s+t)\cos(s^2t)\\z_y=-\sin x\sin y=-\sin(s+t)\sin(s^2t)\end{cases}

x=s+t\implies x_s=x_t=1

y=s^2t\implies\begin{cases}y_s=2st\\y_t=s^2\end{cases}

Putting everything together, we get

z_s=\cos(s+t)\cos(s^2t)-2st\sin(s+t)\sin(s^2t)

z_t=\cos(s+t)\cos(s^2t)-s^2\sin(s+t)\sin(s^2t)

8 0
3 years ago
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Effectus [21]
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4 0
3 years ago
I can't seem to figure this out
antiseptic1488 [7]

Answer:

c. 4

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6 0
3 years ago
Write an appropriate direct variation equation if y = 18 when x = 2
Sergeu [11.5K]

Answer:

y=9x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem we have

y=18 when x=2

Find the value of the constant of proportionality k

k=\frac{y}{x} ----> k=\frac{18}{2}=9

therefore

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y=9x

8 0
3 years ago
An item is regular priced is at $60. It is on sale for 55% off the regular price. What is the sale price?
dalvyx [7]
0.550×$60 = $33
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Therefore, the answer is $27
5 0
3 years ago
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