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3 years ago

Whar is y-2=-3(×+2)

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) is a point on the line

y - 2 = - 3(x + 2) ← is in point- slope form

Hence is the equation of a line with slope = - 3 and passing through the point (2, - 2)

Vanyuwa [196]3 years ago

6 0

Answer:

y-2 = -3( x+2)

y-2 = -3x -6

y+3x = -6 +2 = -4

y+3x = -4

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Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

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Step-by-step explanation:

Given the matrices

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Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

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Whar is y-2=-3(×+2)​

Whar is y-2=-3(×+2)