Law of sines says
a/sinA=b/sinB=c/SinC
where a,b,c are sides of a triangle and A,B,C are angles respectively.
a/sin45.1=c/sin59.1
(we can find angle C by sum of angles of a triangle is 180.)
a=sin(45.1) x 10.2/sin (59.1)
a=0.708 x 10.2/0.85
a=8.496
a=8.5 units
now u can find b and c sides.
Simple...
you have: (2,3) and (-2,6)
Using
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Thus, your answer.
BE and CD are parallel, so the triangles ABE and ACD are similar. Then the following relation holds:
AE/AD = AB/AC
10/(10 + 8) = x/(x + 6)
Solve for x :
10 (x + 6) = x (10 + 8)
10x + 60 = 18x
8x = 60
x = 60/8 = 7/5
Answer:
infinite solutions
Step-by-step explanation:
3x+15=3(x+5)
distribute
3x+15=3x+15
infinite solutions
