PLEASE HELP! I will mark brainliest!
1 answer:
Answer:
D
Step-by-step explanation:
Instead of going through each of the table, let's create one ourselves.
So, we have the piecewise function:
So, let's create a table of values starting with 2 and skipping the odd numbers until 12.
2:
For 2, since 2 is less than one, plug it into the first equation. Thus:
So, the first value is (2,6).
For 4, since 4 is <em>not</em> less than 4 but rather equal to 4, use the second equation. Thus:
The second value is (4,4).
For 6, the same thing. 6 is greater than 4 so use the second equation:
So the third value is (6,6).
And this pattern will repeat. Therefore, our table of equations is:
x | y
2 | 6
4 | 4
6 | 6
8 | 8
10 | 10
12 | 12
The choice that represents this is D. D is the correct answer.
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Answer:
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4
Step-by-step explanation:
The given function is presented as follows;
From the given function, we have;
When x = 1, the denominator of the fraction, , which is (x - 1) = 0, and the function becomes,
therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote
Also we have that in the given function, as <em>x</em> increases, the fraction tends to 0, therefore as x increases, we have;
Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1
When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, . When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left
Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.