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natima [27]
3 years ago
10

PLEASE HELP! I will mark brainliest!

Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Instead of going through each of the table, let's create one ourselves.

So, we have the piecewise function:

f(x)=-x+8,\text{ if } x

So, let's create a table of values starting with 2 and skipping the odd numbers until 12.

2:

For 2, since 2 is less than one, plug it into the first equation. Thus:

f(2)=-(2)+8=6

So, the first value is (2,6).

For 4, since 4 is <em>not</em> less than 4 but rather equal to 4, use the second equation. Thus:

f(4)=(4)=4

The second value is (4,4).

For 6, the same thing. 6 is greater than 4 so use the second equation:

f(6)=(6)=6

So the third value is (6,6).

And this pattern will repeat. Therefore, our table of equations is:

x   |      y

2  |      6

4  |      4

6  |      6

8  |     8

10 |    10

12  |    12

The choice that represents this is D. D is the correct answer.

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Answer:

10 degrees.

Step-by-step explanation:

That would be the angle whose tangent is

17.63 / 100= 0.1763.

That angle is   10 degrees.

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−1.5(4−n)+2.8 how to solve this problem
elena-14-01-66 [18.8K]

−1.5(4−n)+2.8

distribute

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-3.2 + 1.5n


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If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t
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Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}

In point 1:

\to y = (1+ \frac{r}{n})^{nt}

In point 2:

\to \ln (y)= nt \ln(1+  \frac{r}{n})

In point 3:

Its key thing to understand, which would be that you consider the limit n to\infty,  in which r and t were constants!  

=lim_{n \to \ \infty}  \ln (y) =  lim_{n \to \ \infty}  nt \ln(1+\frac{r}{n})\\\\=  lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\=  lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\=  lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\=  lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt

In point 4:

\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt} and

\to \lim_{n \to \ \infty} = A_0e^{rt}

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Step-by-step explanation:

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