The ratio of Dina’s bathing suits to Yana’s bathing suits was 4:1. if Dina has 24 more bathing suits than Yana, how many bathing
1 answer:
Answer: Yana has 8 bathing suits.
Step-by-step explanation: Given that the ratio of Dina’s bathing suits to Yana’s bathing suits was 4 : 1 and Dina has 24 more bathing suits than Yana.
We are to find the number of bathing suits that Yana has.
Let 4x and x represents the number of bathing suits that Dina and Yana have respectively.
Then, according to the given information, we have
Therefore, the number of bathing suits that Yana has is given by
Thus, Yana has 8 bathing suits.
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The first thing you need to do is get the median of the whole set.
The median is the center so since there are 17 numbers the center is 69 and 69 is Q2
Next we need to find Q1 Q3 and Q4 Also, are whiskers are below.
Whisker minimum = 55
Whisker maximum = 91
Now to find Q1 we have to get the median of the first half of the data.
We need to get the median of the following data set.
55, 56, 57, 58, 58, 64, 65, 66
(58+58) / 2 = 58
Q1 = 58
Now we need to find Q3. To do that we get the median of the second half of the data.
75, 77, 78, 81, 81, 85, 86, 91.
(81 + 81) / 2 = 81
Q3 = 81
Now we have all our quartiles and whiskers, which are below, it is time to create our box and whisker plot. Note, create a horizontal or vertical number line with appropriate data. Also the box part is from Q1 to Q3 and your whiskers goes from your minimum to your box and from your maximum to your box.
Whisker Minimum = 55
Q1 = 58
Q2 = 69
Q3 = 81
Whisker Maximum = 91
The median is the center so since there are 17 numbers the center is 69 and 69 is Q2
Next we need to find Q1 Q3 and Q4 Also, are whiskers are below.
Whisker minimum = 55
Whisker maximum = 91
Now to find Q1 we have to get the median of the first half of the data.
We need to get the median of the following data set.
55, 56, 57, 58, 58, 64, 65, 66
(58+58) / 2 = 58
Q1 = 58
Now we need to find Q3. To do that we get the median of the second half of the data.
75, 77, 78, 81, 81, 85, 86, 91.
(81 + 81) / 2 = 81
Q3 = 81
Now we have all our quartiles and whiskers, which are below, it is time to create our box and whisker plot. Note, create a horizontal or vertical number line with appropriate data. Also the box part is from Q1 to Q3 and your whiskers goes from your minimum to your box and from your maximum to your box.
Whisker Minimum = 55
Q1 = 58
Q2 = 69
Q3 = 81
Whisker Maximum = 91
Answer:
The minimum score required for an A grade is 88.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the minimum score required for an A grade.
Top 12%, which is at least the 100-12 = 88th percentile, which is the value of X when Z has a pvalue of 0.88. So it is X when Z = 1.175.
Rounding to the nearest whole number
The minimum score required for an A grade is 88.