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KATRIN_1 [288]
3 years ago
8

What is the domain and range of g(x)= -|x+2| -1

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

g(x)= -|x+2| -1


The domain is the input values, or x values

it is all real number


The range is the output values, or g(x)

the absolute value at is smallest is 0

0-1 is -1  this is the max since the absolute value is multiplied by -1

g(x) <=-1

the output is less than or equal to -1

You might be interested in
How do you check the answer of -6 = x/3
viktelen [127]

Answer:

-6 = x / 3         -Multiply both sides by 3

-6 * 3 = x / 3 * 3

-18 = x

Now, you can check your answer:

-6 = -18 / 3

-6 = -6

Hope this helps!

8 0
3 years ago
Out of 83 children, 39 are boys and 55 have been
Crank
Sounds like an id 10 t problem
5 0
3 years ago
In the adjoining figure O is the centre of the circle the tangent to the circle of radius 6 cm from the exterior point P of the
slamgirl [31]

Answer:

Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.

Let Q be the point onthe circle  in which, tangent make 90° with radius at Q.

PQ = 8 and OQ = 6

we get a right angled triangle  PQO right angled at Q.

so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==

therefore OP =10cm

we need nearest point from P, which is PA

PA = OP - OA= 10 -6=4cm

7 0
2 years ago
Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
____ [38]
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


4 0
3 years ago
I guess u have to find the area
Nesterboy [21]
18
Because 6•3= 18
Hope this helped
7 0
3 years ago
Read 2 more answers
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